sin^2x-5=4sinx

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Solution for sin^2x-5=4sinx equation:


Simplifying
sin2x + -5 = 4sinx

Reorder the terms:
-5 + in2sx = 4sinx

Solving
-5 + in2sx = 4insx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4insx' to each side of the equation.
-5 + -4insx + in2sx = 4insx + -4insx

Combine like terms: 4insx + -4insx = 0
-5 + -4insx + in2sx = 0

Add '5' to each side of the equation.
-5 + -4insx + 5 + in2sx = 0 + 5

Reorder the terms:
-5 + 5 + -4insx + in2sx = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -4insx + in2sx = 0 + 5
-4insx + in2sx = 0 + 5

Combine like terms: 0 + 5 = 5
-4insx + in2sx = 5

Reorder the terms:
-5 + -4insx + in2sx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -4insx + in2sx = 0

The solution to this equation could not be determined.

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